快慢指针：删除有序数组中的重复项
题目链接：. - 力扣（LeetCode）
思路好想，代码实现不好想
class Solution {public int removeDuplicates(int[] nums) {int fast = 1,slow = 1;while(fast < nums.length){if(nums[fast] != nums[fast-1]){nums[slow] = nums[fast];slow++;}fast++;}return slow;}
}
题目链接：. - 力扣（LeetCode）
思路好想，代码实现不好想
class Solution {public int removeDuplicates(int[] nums) {int fast = 1,slow = 1;while(fast < nums.length){if(nums[fast] != nums[fast-1]){nums[slow] = nums[fast];slow++;}fast++;}return slow;}
}