用c语言实现简易三子棋
本篇适用于C语言初学者。
目录
完整代码：
分步介绍：
声明：
代码主体部分：
模块功能实现：
完整代码：
#include<stdio.h>
#include <stdlib.h>
#include <time.h>#define ROW 3
#define COL 3void InitBorad(char borad[ROW][COL], int row, int col);void DisplayBorad(char borad[ROW][COL], int row, int col);void PlayerMove(char borad[ROW][COL], int row, int col);void ComputerMove(char borad[ROW][COL], int row, int col);char IsWin(char borad[ROW][COL], int row, int col);void InitBorad(char borad[ROW][COL], int row, int col)
{int i = 0;for (i = 0; i < row; i++){int j = 0;for (j = 0; j < col; j++){borad[i][j] = ' ';}}
}void DisplayBorad(char borad[ROW][COL], int row, int col)
{int i = 0;for (i = 0; i < row; i++){int j = 0;for (j = 0; j < col; j++){printf(" %c ", borad[i][j]);if(j < col - 1)printf("|");}printf("\n");if (i < row - 1){for (j = 0; j < col; j++){printf("---");if (j < col - 1)printf("|");}}printf("\n");}
}void PlayerMove(char borad[ROW][COL], int row, int col)
{int x = 0;int y = 0;while (1){printf("玩家下棋:>");scanf("%d %d", &x, &y);if (x >= 1 && x <= row && y >= 1 && y <= col){if (borad[x - 1][y - 1] == ' '){borad[x - 1][y - 1] = '*';break;}else{printf("该位置已被占有，请重新选择!\n");}}else{printf("输入错误，请重新选择！\n");}}
}void ComputerMove(char borad[ROW][COL], int row, int col)
{printf("电脑下棋:>\n");while (1){int x = rand() % row;int y = rand() % col;if (borad[x][y] == ' '){borad[x][y] = '#';break;}}
}//'*'玩家赢
//'#'电脑赢
//'C'继续游戏
//'Q'平局
//char IsWin(char borad[ROW][COL], int row, int col)
//{
// int i = 0;
// for (i = 0; i < row; i++)
// {
// if (borad[i][0] == borad[i][1] && borad[i][1] == borad[i][2] && borad[i][0] != ' ')
// return borad[i][0];
// }
// for (i = 0; i < col; i++)
// {
// if (borad[0][i] == borad[1][i] && borad[1][i] == borad[2][i] && borad[0][i] != ' ')
// return borad[0][i];
// }
// if (borad[0][0] == borad[1][1] && borad[1][1] == borad[2][2] && borad[0][0] != ' ')
// return borad[0][0];
// if (borad[0][2] == borad[1][1] && borad[1][1] == borad[2][0] && borad[0][2] != ' ')
// return borad[0][2];
// for (i = 0; i < row; i++)
// {
// int j = 0;
// for (j = 0; j < col; j++)
// {
// if (borad[i][j] == ' ')
// return 'C';
// }
// }
// return 'Q';
//}//判断优化
char IsWin(char borad[ROW][COL], int row, int col)
{int i = 0;int flag = 1;//行for (i = 0; i < row; i++){flag = 1;int n = 0;if (borad[i][0] != ' '){while (n < row - 1){if (borad[i][n] != borad[i][n + 1]){flag = 0;break;}n++;}if (flag)return borad[i][0];}}//列for (i = 0; i < col; i++){flag = 1;int n = 0;if (borad[0][i] != ' '){while (n < col - 1){if (borad[n][i] != borad[n + 1][i]){flag = 0;break;}n++;}if (flag)return borad[0][i];}}//左对角线if (borad[0][0] != ' '){flag = 1;int n = 0;while (n < row - 1){if (borad[n][n] != borad[n + 1][n + 1]){flag = 0;break;}n++;}if (flag)return borad[0][0];}//右对角线int r = 0;int c = col - 1;if (borad[r][c] != ' '){flag = 1;while (r < row - 1){if (borad[r][c] != borad[r + 1][c - 1]){flag = 0;break;}r++;c--;}if (flag)return borad[r][c];}//继续for (i = 0; i < row; i++){int j = 0;for (j = 0; j < col; j++){if (borad[i][j] == ' ')return 'C';}}//平局return 'Q';
}void menu()
{printf("**********************************\n");printf("********** 1.play ***********\n");printf("********** 0.exit ***********\n");printf("**********************************\n");
}void game()
{char borad[ROW][COL] = { 0 };char ch = 0;//初始化InitBorad(borad, ROW, COL);//打印棋盘DisplayBorad(borad, ROW, COL);//玩家下棋while (1){//玩家下棋PlayerMove(borad, ROW, COL);DisplayBorad(borad, ROW, COL);//判断ch = IsWin(borad, ROW, COL);if (ch != 'C')break;//电脑下棋ComputerMove(borad, ROW, COL);DisplayBorad(borad, ROW, COL);ch = IsWin(borad, ROW, COL);if (ch != 'C')break;}if (ch == '*')printf("玩家赢！\n");else if (ch == '#')printf("电脑赢！\n");else if (ch == 'Q')printf("平局！\n");
}int main()
{int input = 0;srand((unsigned int)time(NULL));do{menu();printf("请选择:>");scanf("%d", &input);switch (input){case 1:game();break;case 0:printf("退出游戏！\n");break;default:printf("输入错误，请重新选择!\n");break;}} while (input);return 0;
}分步介绍：
声明：
#include<stdio.h>
#include <stdlib.h>
#include <time.h>//定义表示符常量分别表示行（ROW）和列（COL）
#define ROW 3
#define COL 3
//初始化棋盘
void InitBorad(char borad[ROW][COL], int row, int col);
//打印棋盘
void DisplayBorad(char borad[ROW][COL], int row, int col);
//玩家移动
void PlayerMove(char borad[ROW][COL], int row, int col);
//电脑移动
void ComputerMove(char borad[ROW][COL], int row, int col);
//判断输赢实现
char IsWin(char borad[ROW][COL], int row, int col);代码主体部分：
//游戏菜单
void menu()
{printf("**********************************\n");printf("********** 1.play ***********\n");printf("********** 0.exit ***********\n");printf("**********************************\n");
}void game()
{//定义一个模拟棋盘的二维数组char borad[ROW][COL] = { 0 };char ch = 0;//调用函数初始化棋盘（二维数组）InitBorad(borad, ROW, COL);//调用函数打印棋盘（二维数组）DisplayBorad(borad, ROW, COL);while (1){//调用函数玩家下棋PlayerMove(borad, ROW, COL);DisplayBorad(borad, ROW, COL);//进行输赢判断ch = IsWin(borad, ROW, COL);//C表示继续游戏 if (ch != 'C')break;//调用函数电脑下棋ComputerMove(borad, ROW, COL);//进行输赢判断DisplayBorad(borad, ROW, COL);ch = IsWin(borad, ROW, COL);if (ch != 'C')break;}// * 表示玩家赢if (ch == '*')printf("玩家赢！\n");// # 表示电脑赢else if (ch == '#')printf("电脑赢！\n");//Q表示平局else if (ch == 'Q')printf("平局！\n");
}
//主函数（程序入口）
int main()
{//存储选择的变量int input = 0;//使用time()库（time.h）函数和srand()库（stdlib.h）函数确定随机数生成起点,将time()返回值强制转换成无符号整型（unsigned int）。srand((unsigned int)time(NULL));do{//打印游戏菜单menu();//选择开始游戏或者退出游戏printf("请选择:>");scanf("%d", &input);switch (input){case 1:game();break;case 0:printf("退出游戏！\n");break;default :printf("输入错误，请重新选择!\n");break;}} while (input);return 0;
}模块功能实现：
//利用嵌套循环实现对棋盘（二维数组）的初始化，初始化为空格
void InitBorad(char borad[ROW][COL], int row, int col)
{int i = 0;for (i = 0; i < row; i++){int j = 0;for (j = 0; j < col; j++){borad[i][j] = ' ';}}
}
//利用嵌套循环实现对棋盘的打印
void DisplayBorad(char borad[ROW][COL], int row, int col)
{int i = 0;for (i = 0; i < row; i++){int j = 0;for (j = 0; j < col; j++){printf(" %c ", borad[i][j]);if(j < col - 1)printf("|");}printf("\n");if (i < row - 1){for (j = 0; j < col; j++){printf("---");if (j < col - 1)printf("|");}}printf("\n");}
}
//玩家下棋实现细节
void PlayerMove(char borad[ROW][COL], int row, int col)
{int x = 0;int y = 0;while (1){printf("玩家下棋:>");//输入想要下棋地方的坐标：行从1开始，列从1开始（数组下标从0开始，因此需要对输入数据减1）scanf("%d %d", &x, &y);//对输入信息所对应的坐标进行判断和处理if (x >= 1 && x <= row && y >= 1 && y <= col){if (borad[x - 1][y - 1] == ' '){borad[x - 1][y - 1] = '*';break;}else{printf("该位置已被占有，请重新选择!\n");}}else{printf("输入错误，请重新选择！\n");}}
}
//电脑下棋实现细节
void ComputerMove(char borad[ROW][COL], int row, int col)
{printf("电脑下棋:>\n");while (1){//代码主体部分已通过srand()设置随机数生成起点，此处调用rand()库（stdlib.h）函数生成两个随机数，分别作为二维数组的行下标和列下标int x = rand() % row;int y = rand() % col;//对坐标进行判断和处理if (borad[x][y] == ' '){borad[x][y] = '#';break;}}
}//'*'玩家赢
//'#'电脑赢
//'C'继续游戏
//'Q'平局
//此注释内容为原始判断方法实现内容
//char IsWin(char borad[ROW][COL], int row, int col)
//{
// int i = 0;
// for (i = 0; i < row; i++)
// {
// if (borad[i][0] == borad[i][1] && borad[i][1] == borad[i][2] && borad[i][0] != ' ')
// return borad[i][0];
// }
// for (i = 0; i < col; i++)
// {
// if (borad[0][i] == borad[1][i] && borad[1][i] == borad[2][i] && borad[0][i] != ' ')
// return borad[0][i];
// }
// if (borad[0][0] == borad[1][1] && borad[1][1] == borad[2][2] && borad[0][0] != ' ')
// return borad[0][0];
// if (borad[0][2] == borad[1][1] && borad[1][1] == borad[2][0] && borad[0][2] != ' ')
// return borad[0][2];
// for (i = 0; i < row; i++)
// {
// int j = 0;
// for (j = 0; j < col; j++)
// {
// if (borad[i][j] == ' ')
// return 'C';
// }
// }
// return 'Q';
//}//判断优化
//'*'玩家赢
//'#'电脑赢
//'C'继续游戏
//'Q'平局
char IsWin(char borad[ROW][COL], int row, int col)
{int i = 0;int flag = 1;//行的判断实现//循环遍历行for (i = 0; i < row; i++){//作为实现判断依据的变量，假设游戏已经结束。flag = 1;//作为遍历一行内容的变量int n = 0;if (borad[i][0] != ' '){while (n < row - 1){if (borad[i][n] != borad[i][n + 1]){//如果本行三个落棋地方不一样，置flag变量为0，表示游戏未结束flag = 0;break;}n++;}//如果游戏结束，返回达成胜利条件坐标所存的字符作为判断玩家or电脑赢的依据if (flag)return borad[i][0];}}//列//具体实现细节同行for (i = 0; i < col; i++){flag = 1;int n = 0;if (borad[0][i] != ' '){while (n < col - 1){if (borad[n][i] != borad[n + 1][i]){flag = 0;break;}n++;}//如果游戏结束，返回达成胜利条件坐标所存的字符作为判断玩家or电脑赢的依据if (flag)return borad[0][i];}}//左对角线//左对角线规律：行加一，列加一。 剩余实现原理同行if (borad[0][0] != ' '){flag = 1;int n = 0;while (n < row - 1){if (borad[n][n] != borad[n + 1][n + 1]){flag = 0;break;}n++;}//如果游戏结束，返回达成胜利条件坐标所存的字符作为判断玩家or电脑赢的依据if (flag)return borad[0][0];}//右对角线//右对角线规律：开始时行为零（数组）列为col - 1，此后行加一，列减一，直至行为数组下标最大值或者列为0。 剩余实现原理同行int r = 0;int c = col - 1;if (borad[r][c] != ' '){flag = 1;while (r < row - 1){if (borad[r][c] != borad[r + 1][c - 1]){flag = 0;break;}r++;c--;}//如果游戏结束，返回达成胜利条件坐标所存的字符作为判断玩家or电脑赢的依据if (flag)return borad[r][c];}//继续//前面判断并未生效，因此说明此时未有赢家诞生，对数组进行遍历，看看是否还有可以落棋的地方来判断是否游戏继续或者平局for (i = 0; i < row; i++){int j = 0;for (j = 0; j < col; j++){//如果有 ' ' 证明有地方可以落棋，返回 'C' 表示游戏继续 if (borad[i][j] == ' ')return 'C';}}//平局//如果上述判断均未生效，且遍历数组发现没有可以落棋的坐标返回'Q'表示平局return 'Q';
}