C语言 | Leetcode C语言题解之第477题汉明距离总和
题目：
题解：
int totalHammingDistance(int* nums, int numsSize) {int ans = 0;for (int i = 0; i < 30; ++i) {int c = 0;for (int j = 0; j < numsSize; ++j) {c += (nums[j] >> i) & 1;}ans += c * (numsSize - c);}return ans;
}
题目：
题解：
int totalHammingDistance(int* nums, int numsSize) {int ans = 0;for (int i = 0; i < 30; ++i) {int c = 0;for (int j = 0; j < numsSize; ++j) {c += (nums[j] >> i) & 1;}ans += c * (numsSize - c);}return ans;
}