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LeetCode707 设计链表

news 2025/8/16 10:59:24

前言

题目： 707. 设计链表
文档： 代码随想录——设计链表
编程语言： C++
解题状态： 代码功底不够，只能写个大概

思路

主要考察对链表结构的熟悉程度，对链表的增删改查，比较考验代码功底以及对链表的掌握。本题中的一些边界条件也要注意。

代码

class MyLinkedList {
public:struct ListNode {int val;ListNode* next;ListNode(int x) : val(x), next(nullptr) {}};MyLinkedList() {_dummyHead = new ListNode(0);_size = 0;}int get(int index) {if (index > (_size - 1) || index < 0) {return -1;}ListNode* cur = _dummyHead -> next;while (index--) {cur = cur -> next;}return cur -> val;}void addAtHead(int val) {ListNode* newNode = new ListNode(val);newNode -> next = _dummyHead -> next;_dummyHead -> next = newNode;_size++;}void addAtTail(int val) {ListNode* newNode = new ListNode(val);ListNode* cur = _dummyHead;while (cur -> next != nullptr) {cur = cur -> next;}cur -> next = newNode;_size++;}void addAtIndex(int index, int val) {if (index > _size) {return;}ListNode* newNode = new ListNode(val);ListNode* cur = _dummyHead;while (index--) {cur = cur -> next;}newNode -> next = cur -> next;cur -> next = newNode;_size++;}void deleteAtIndex(int index) {if (index >= _size || index < 0) {return;}ListNode* cur = _dummyHead;while (index--) {cur = cur -> next;}ListNode* tmp = cur -> next;cur -> next = cur -> next -> next;delete tmp;_size--;}void printLinkedList() {ListNode* cur = _dummyHead;while (cur -> next != nullptr) {cout << cur -> next -> val << " ";cur = cur -> next;}cout << endl;}private:int _size;ListNode* _dummyHead;
};