N 字形变换
N 字形变换
题目:
将一个给定字符串 s 根据给定的行数 numRows ,以从上往下、从左到右进行 Z 字形排列。比如输入字符串为 "PAYPALISHIRING" 行数为 3 时,排列如下:P A H N
A P L S I I G
Y I R
之后,你的输出需要从左往右逐行读取,产生出一个新的字符串,比如:"PAHNAPLSIIGYIR"。请你实现这个将字符串进行指定行数变换的函数:string convert(string s, int numRows);示例 1:
输入:s = "PAYPALISHIRING", numRows = 3
输出:"PAHNAPLSIIGYIR"示例 2:
输入:s = "PAYPALISHIRING", numRows = 4
输出:"PINALSIGYAHRPI"
解释:
P I N
A L S I G
Y A H R
P I示例 3:
输入:s = "A", numRows = 1
输出:"A"
解题思路: 创建 numRows 长度的数组然后遍历字符串将每个字符放到对应下标的数组中即可
class Solution {public String convert(String s, int numRows) {int len = s.length();if(len == 1 || numRows == 1) {return s;}List<StringBuilder> list = new ArrayList(numRows);for(int i = 0; i < numRows; i++) {list.add(new StringBuilder());}int cur = 0;char[] ch = s.toCharArray();boolean flag = true;for(int i = 0; i < ch.length; i++) {char c = ch[i];list.get(cur).append(c);if(cur == 0 && i != 0) {flag = !flag;}if(cur == numRows - 1) {flag = !flag;}cur = cur + (flag ? 1 : -1);}StringBuilder ans = new StringBuilder();for(StringBuilder sb : list) {ans.append(sb.toString());}return ans.toString(); }
}