【Mysql】关联查询1对多处理
关联查询1对多返回
遇见的问题
审批主表,和审批明细表,一张审批对应多张明细数据,每条明细数据的状态是不一样的,现在需要根据明细的状态获取到主单子的状态,状态返回矩阵如下
明细状态 | 返回总状态 |
---|---|
都是已完成 | 已完成 |
都是已终止 | 已终止 |
有进行中 | 进行中 |
有草稿 | 草稿 |
只有已完成和已终止 | 已完成 |
观察报错
无
问题解决
SELECT vba.object_id,vba.create_time,vba.company_id,vba.approval_no,vba.finish_time,vba.business_table,vba.business_id,t2.enum_status,vba.create_user_name,vba.apply_abstract
FROM view_bus_approval vbaLEFT JOIN view_bus_payment vbp ON vba.object_id = vbp.approval_idLEFT JOIN (SELECT ba.approval_id,CASEWHEN ba.enum_status = '05'AND ba.cnt > 0 THEN'05'WHEN ba.enum_status = '10'AND ba.cnt > 0 THEN'10'WHEN ba.enum_status = '20'AND ba.cnt = ba1.cnt THEN'20'WHEN ba.enum_status = '30'AND ba.cnt = ba1.cnt THEN'30'WHEN ba.enum_status = '40'AND ba.cnt = ba1.cnt THEN'40'ELSE '20'END AS enum_statusFROM (SELECT t2.approval_id,t2.enum_status,sum(cnt) AS cntFROM view_approval_detail_status_cnt t2WHERE t2.approval_user_id = 1GROUP BY t2.approval_id,t2.enum_status) baLEFT JOIN (SELECT t2.approval_id, sum(cnt) AS cntFROM view_approval_detail_status_cnt t2WHERE t2.approval_user_id = 1GROUP BY t2.approval_id) ba1 ON ba1.approval_id = ba.approval_idGROUP BY ba.approval_id) t2 ON t2.approval_id = vba.object_id
WHERE vba.is_deleted = 0AND vba.business_table = 'bus_official_seal_use'
ORDER BY (CASEvba.enum_statusWHEN '05' THEN1WHEN '30' THEN2WHEN '10' THEN3WHEN '40' THEN4WHEN '20' THEN5ELSE 6END) ASC,vba.create_time DESC;
这里用到了两层查询,一遍是查询该申请单子的所有明细的数量
SELECT t2.approval_id, sum(cnt) AS cnt
FROM view_approval_detail_status_cnt t2
WHERE t2.approval_user_id = 1
GROUP BY t2.approval_id
然后外层是查询该单子下再按照状态进行分组求和
SELECT t2.approval_id,t2.enum_status,sum(cnt) AS cnt
FROM view_approval_detail_status_cnt t2
WHERE t2.approval_user_id = 1
GROUP BY t2.approval_id,t2.enum_status
然后拿到的申请单id,再group by这个单子id,因为一个单子只会返回一个状态,就达到效果了。
结语
如果哪位大佬发现了解释的不对的,还望不吝赐教。十分感谢