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vue2+Spring Boot2.7 大文件分片上传

news 2025/9/13 8:40:30

之前我们文章手把手带大家实现 vue2+Spring Boot2.7 文件上传功能将了上传文件
但如果文件很大就不太好处理了按正常情况甚至因为超量而报错

这里我弄了个足够大的文件
在这里插入图片描述
我们先搭建 Spring Boot2.7 环境
首先 application.yml 代码编写如下

server:port: 80
upload:path: D:/upload/
spring:servlet:multipart:max-file-size: 500MBmax-request-size: 500MB

这里我们改了他对请求大小的限制不然你上次300M左右的东西系统直接抛异常了

然后我们将FileUploadController 类代码更改如下

package com.example.javadom.controller;import org.springframework.beans.factory.annotation.Value;
import org.springframework.http.HttpStatus;
import org.springframework.http.ResponseEntity;
import org.springframework.web.bind.annotation.PostMapping;
import org.springframework.web.bind.annotation.RequestParam;
import org.springframework.web.bind.annotation.RestController;
import org.springframework.web.multipart.MultipartFile;import java.io.File;
import java.io.IOException;@RestController
public class FileUploadController {//读取配置文件中的 upload下的path@Value("${upload.path}")private String uploadPath;@PostMapping("/upload")public ResponseEntity<String> uploadFile(@RequestParam("file") MultipartFile file) {// 处理上传逻辑，可以根据需要保存文件到指定目录// 这里假设保存到D:/upload/目录下try {String filePath = uploadPath + file.getOriginalFilename();file.transferTo(new File(filePath));// 进行后续处理，比如返回成功消息给前端return ResponseEntity.ok("File uploaded successfully");} catch (IOException e) {e.printStackTrace();// 发生错误时，返回错误消息给前端return ResponseEntity.status(HttpStatus.INTERNAL_SERVER_ERROR).body("Failed to upload file");}}
}

然后我们vue代码将 App.vue改成这样

<template><div><input type="file" @change="onFileChange" /><button @click="uploadFile">Upload</button><div v-if="uploadProgress !== null">Upload progress: {{ uploadProgress }}%</div></div>
</template><script>
import axios from 'axios';export default {data() {return {file: null,uploadProgress: null,};},methods: {onFileChange(event) {this.file = event.target.files[0];},uploadFile() {const formData = new FormData();formData.append('file', this.file);axios.post('/upload', formData, {headers: {'Content-Type': 'multipart/form-data',},onUploadProgress: (progressEvent) => {this.uploadProgress = Math.round((progressEvent.loaded / progressEvent.total) * 100);},}).then((response) => {console.log('Upload successful',response);}).catch((error) => {console.error('Upload failed', error);});},},
};
</script>