b站视频:https://www.bilibili.com/video/BV1iS4y1e7MJ/?spm_id_from=333.999.0.0&vd_source=1717654b9cbbc6a773c2092070686a95
"""
特点:
1、一定要有递推式(显示、隐式,也有过程)
2、一定要有递归的出口(为了避免一直执行,一定要中止程序)(一般要写在函数的开头)
3、一定要定义函数(函数自己调用自己)
4、比较耗内存(斐波那契数列重复计算f(3))
"""
"""
递归需要注意的地方:
1、会耗费大量的内存(重复计算),所以用递归一定要谨慎,如果电脑内存不够大,就不要用递归(例如计算斐波那契数列)
"""
"""
1、递推式:
f(1)=1
f(2)=f(1)+1
f(3)=f(2)+1
f(4)=f(3)+1
.
.
.
f(n)=f(n-1)+12、出口
f(1)=1
"""def f(n):if n == 1:return 1else:return f(n-1) + 1a = f(5)
print(a)
def f(n):if n == 1:return 0elif n == 2:return 1else:return f(n - 1) + f(n - 2)print(f(6))
def f(n):if n == 1:return 1elif n == 2:return 2elif n == 3:return 4else:return f(n - 1) + f(n - 2) + f(n - 3)print(f(5))
def f(m1, m2):global list1if m1 == m2:returnfor i in range(m1, m2):if list1[i] > list1[i + 1]:list1[i], list1[i + 1] = list1[i + 1], list1[i]f(m1, m2 - 1)list1 = [12, 11, 5, 6, 7, 18]
f(0, len(list1) - 1)
print(list1)
def f(n):if n == 1:return 1else:return n + f(n - 1)print(f(10))list1 = [12, 14, 15, 8, 7]def f(n):if n == 1:return list1[0]else:return max(f(n - 1), list1[n - 1])print(f(len(list1)))
num = 1def f(m1, m2):global numfor i in range(m1, m2):if m2 % i == 0 and m2 // i >= i:num += 1f(i, m2 // i)f(2, 36)
print(num)