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没有jodatime，rust怎么方便高效的操作时间呢？

news 2025/8/1 12:56:27

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当使用Rust进行日期操作时，可以使用 chrono 库。下面给出了二十个常见的日期操作的例子：

1. 获取当前日期和时间：

use chrono::prelude::*;let current_datetime = Local::now();
println!("Current datetime: {}", current_datetime);

2. 获取当前日期：

use chrono::prelude::*;let current_date = Local::today();
println!("Current date: {}", current_date);

3. 获取当前时间：

use chrono::prelude::*;let current_time = Local::now().time();
println!("Current time: {}", current_time);

4. 根据年、月、日创建日期：

use chrono::{NaiveDate, Local};let date = NaiveDate::from_ymd(2022, 1, 1);
println!("Date: {}", date);

5. 根据时、分、秒创建时间：

use chrono::{NaiveTime, Local};let time = NaiveTime::from_hms(12, 34, 56);
println!("Time: {}", time);

6. 将日期和时间合并为日期时间：

use chrono::{NaiveDate, NaiveTime, NaiveDateTime};let date = NaiveDate::from_ymd(2022, 1, 1);
let time = NaiveTime::from_hms(12, 34, 56);
let datetime = NaiveDateTime::new(date, time);
println!("Datetime: {}", datetime);

7. 格式化日期时间为字符串：

use chrono::{NaiveDateTime, format::strftime};let datetime = NaiveDateTime::parse_from_str("2022-01-01 12:34:56", "%Y-%m-%d %H:%M:%S").unwrap();
let formatted_datetime = datetime.format("%Y-%m-%d %H:%M:%S").to_string();
println!("Formatted datetime: {}", formatted_datetime);

8. 在日期上进行加减操作：

use chrono::{NaiveDate, Duration};let date = NaiveDate::from_ymd(2022, 1, 1);
let new_date = date + Duration::days(7);
println!("New date: {}", new_date);

9. 计算两个日期之间的天数差：

use chrono::{NaiveDate, Duration};let date1 = NaiveDate::from_ymd(2022, 1, 1);
let date2 = NaiveDate::from_ymd(2022, 1, 10);
let duration = date2.signed_duration_since(date1);
let days_diff = duration.num_days();
println!("Days difference: {}", days_diff);

10. 比较两个日期的先后：

use chrono::{NaiveDate, Ordering};let date1 = NaiveDate::from_ymd(2022, 1, 1);
let date2 = NaiveDate::from_ymd(2022, 1, 10);
let ordering = date1.cmp(&date2);
println!("Date1 is {:?} Date2", ordering);

11. 获取当前月份：

use chrono::prelude::*;let current_month = Local::today().month();
println!("Current month: {}", current_month);

12. 获取当前年份：

use chrono::prelude::*;let current_year = Local::today().year();
println!("Current year: {}", current_year);

13. 获取当前日期是星期几：

use chrono::prelude::*;let current_weekday = Local::today().weekday();
println!("Current weekday: {}", current_weekday);

14. 获取指定日期的年份：

use chrono::prelude::*;let date = NaiveDate::from_ymd(2022, 1, 1);
let year = date.year();
println!("Year: {}", year);

15. 获取指定日期的月份：

use chrono::prelude::*;let date = NaiveDate::from_ymd(2022, 1, 1);
let month = date.month();
println!("Month: {}", month);

16. 获取指定日期的日：

use chrono::prelude::*;let date = NaiveDate::from_ymd(2022, 1, 1);
let day = date.day();
println!("Day: {}", day);

17. 获取指定日期是星期几：

use chrono::prelude::*;let date = NaiveDate::from_ymd(2022, 1, 1);
let weekday = date.weekday();
println!("Weekday: {}", weekday);

18. 获取指定日期所在月份的天数：

use chrono::prelude::*;let date = NaiveDate::from_ymd(2022, 2, 1);
let days_in_month = date.with_day0(0).unwrap().day();
println!("Days in month: {}", days_in_month);

19. 根据日期计算年龄：

use chrono::prelude::*;let birthday = NaiveDate::from_ymd(1990, 5, 15);
let today = Local::today().naive_local();
let age = today.year() - birthday.year();
println!("Age: {}", age);

20. 判断是否为闰年：

use chrono::prelude::*;let year = 2024;
let is_leap_year = NaiveDate::from_ymd_opt(year, 2, 29).is_some();
println!("Is leap year: {}", is_leap_year);