LeetCode 高频 SQL 50 题（基础版）之 【连接】部分 · 下

题解：

select r.name,b.bonus from Employee r left join Bonus b on r.empId=b.empId
where b.bonus <1000 or b.bonus is null

题解：

select stu.student_id student_id, stu.student_name student_name,sub.subject_name subject_name,
count(ex.student_id) attended_exams
from Students stu 
join Subjects sub
left join Examinations ex 
on stu.student_id = ex.student_id and sub.subject_name = ex.subject_name
group by stu.student_id ,sub.subject_name
order by stu.student_id ,sub.subject_name

题解：

select name from Employee
where id in (select managerId from Employeegroup by managerIdhaving count(managerId)>=5
)

题解：

select s.user_id user_id, round( ifnull(avg(c.action='confirmed'),0),2) confirmation_rate from Signups s left join Confirmations c
on s.user_id = c.user_id
group by s.user_id